1Win Aviator Best Strategies and Tricks

To obtain the best results in gambling, a gamer may use the 1Win Aviator tricks. Even though Aviator is a game of chance, a player can impact the winning probability by following simple but efficient recommendations. To name a few tips, a player should:

• Know the rules of the game, its functionality, and all the features to improve his gambling experience and get the most out of the gameplay. The rules can be found directly on the game page. There is “How to play” in its header;
• Analyze the results of other players whose outcomes are displayed in the statistics, ask questions via live chat, and take part in discussions when someone shares his opinions;
• Learn the statistics of previous odds. If the odds were low within several rounds in succession, there is a strong possibility that high odds are starting to appear. However, this cause-and-effect Aviator game trick does not always work;
• Start with small amounts to place bets and cash out at a low multiplier. This 1Win Aviator strategy helps a player increase his winning chances to a significant percentage and reduce losses if they still happen;
• Manage the bankroll by setting a limit on losses. A gambler may find it challenging to interrupt when it is time because they are enjoying the thrill of the race. That is why it is vital to take security measures, build up a thought-out gaming budget, and understand that gambling is entertainment that should be fun but not addictive;
• Benefit from the “Auto” option that allows him to cash out automatically. As a result, this 1Win Aviator trick helps a player avoid emotions related to the decision-making process.

Probably, it is the simplest 1Win Aviator strategy that can bring a large winning prize after numerous lost rounds. It can be tried by those players who can afford a large bankroll.

The Martingale Aviator strategy is considered a negative progressive system that is applied to any game where the outcome is based on a 1 in 2 chance. When using it, a player is expected to double the amount of his bet after each loss.

Example:

• If the first bet amounting to 20 INR is lost, the second bet should be 40 INR; if it is lost, too, the third one should be 80 INR;
• If the third bet is placed at a multiplier of 2x and a player wins, he will get 80 INR x 2 = 160 INR;
• The total amount of his losses is 60 INR (20 INR plus 40 INR);
• Thus, the prize is high enough to exceed the previous losses and bring a profit equal to 160 minus 20 minus 40 minus 80 = 20 INR.

Aviator is a fair game with frequent winning outcomes. Actually, almost every round can bring a winning prize if a player cashes out at a very low multiplier. But to win more, take the risk of missing an opportunity to withdraw while a plane is flying. Then, you can benefit from the Martingale 1Win Aviator strategy that is popular among gamblers all over the world.

The D’Alembert system is good for those who want to keep their bankroll under strict control. It can be considered a conservative negative progression system that provides a player with small winning prizes. However, it allows the user to reduce losses.

The concept of this 1Win Aviator strategy is extremely simple. A player increases the amount of his bet when he loses and decreases it when he wins. Thus, if he wins after a loss, his increased bet value will cover the previous loss. And when he refuses to continue with high bets, he manages the bankroll, avoiding significant losses.

Example:

• If a player places a bet equal to 20 INR and wins, he continues with the same amount.
• When he loses a round, he increases the initial value and bets 40 INR.
• If he loses again, he adds the initial value to the previous amount and bets 60 INR.
• If he wins, he decreases 60 INR by 20 INR and places a bet equal to 40 INR, and so on.

Example:

• The row of positive numbers is 1, 2, 3;
• A gambler places a bet equal to the sum of “1” and 3,” which is 4;
• He wins and removes “1” and “3” from the row;
• The row of positive numbers is 2;
• He places a bet equal to 2;
• He loses and adds the amount of his previous bet to the row (2, 2);
• He places a bet equal to 4 (2+2);
• He loses again, and the row becomes 2, 2, 4;
• He places his next bet equal to 6 (2 + 4), and so on.